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ddde\e]gdeZgdd	dde_ddddddde[gdgdddde_ddddddde[gde[e[gdddde_dddddddgde\gdddde_ddddddde\e]gdgdddde_ddddde6dgde[gdddde_dddddedgde[gdddd e_dd!dd"dedgde[gdddd#e_dd$dd%de6dgdgdddd&e_dd'dd(dedgdgdddd)e_dd*dd+dedgdgdddd,e_dd-dd.ddde[gde[gdd	dd/e_dd0dd1dedgde[gdddd2e_dd3dd4dedgde[gdddd5e_dd6dd7dedgde[gdddd8e_dd9dd:de!dgde[gdddd;e_dd<dd=dddeOeOgde[gdd	dd>e_dd?dd@ddde[e[gde[gddddAe_ddBddCddde[e[gde[gddddDe_ddEddFde!de\e]gde[gddddGe_ddHddIddde\e[e]gde[gddddJe_ddKddLddde[e[gde[gddddMe_ddNddOddde[e[e[gde[gdd	ddPe_ddQddRdedgdgddddSe_ddTddUddde[gdgddddVe_ddWddXdedgdgdd	ddYe_ddZdd[dedgde[gdddd\e_dd]dd^ddde[gde[gdddd_gAZ`[_iZaiZbxece`D]\ZdZeeejfeakregd`eejfeaeejfedfeejhebkregdaeejhebeejhedfedeaeejf<edebeejh<qW[a[b[d[eiZixe`D]Zeeeeieejh<q-W[edbdcddZjej[jdbdedfZkdgdZldhdZmddd	ddidZnGdjdkdkZodlZpdmZqdnepdoeqiZrdpdqZsetdrkrddluZueujvdsdtZwewjxdudveujydwdxdydzd{ewjxd|d}d~ejzdveujyddzdewjxdddddzdewjxddd~d	dveBdzdewjxdddddzdewjxddd~ddzdewjxdddddzdewjxddddzdewj{Z|e|j}r&esne|j~r5dndZ~e|jrRewjnee|jdkrene|jde|jde|je~nqe|jrindZxYe|jD]NZe|jjdejfZe|jjedenee|jee|je~qWdS(ar"Executable documentation" for the pickle module.

Extensive comments about the pickle protocols and pickle-machine opcodes
can be found here.  Some functions meant for external use:

genops(pickle)
   Generate all the opcodes in a pickle, as (opcode, arg, position) triples.

dis(pickle, out=None, memo=None, indentlevel=4)
   Print a symbolic disassembly of a pickle.
Ndisgenopsoptimizec@s"eZdZdZddZdS)	ArgumentDescriptornamenreaderdoccCst|tst||_t|trT|dksZ|ttttt	fksZt||_
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rzOne-byte unsigned integer.cCsB|jd}t|dkr2td|dStddS)z
    >>> import io
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    255
    >>> read_uint2(io.BytesIO(b'\xff\xff'))
    65535
    rz<Hrz'not enough data in stream to read uint2N)r!len_unpackr")r#r$rrr
read_uint2s	r)uint2z)Two-byte unsigned integer, little-endian.cCsB|jd}t|dkr2td|dStddS)z
    >>> import io
    >>> read_int4(io.BytesIO(b'\xff\x00\x00\x00'))
    255
    >>> read_int4(io.BytesIO(b'\x00\x00\x00\x80')) == -(2**31)
    True
    rz<irz&not enough data in stream to read int4N)r!r'r(r")r#r$rrr	read_int4s	r+int4z8Four-byte signed integer, little-endian, 2's complement.cCsB|jd}t|dkr2td|dStddS)z
    >>> import io
    >>> read_uint4(io.BytesIO(b'\xff\x00\x00\x00'))
    255
    >>> read_uint4(io.BytesIO(b'\x00\x00\x00\x80')) == 2**31
    True
    rz<Irz'not enough data in stream to read uint4N)r!r'r(r")r#r$rrr
read_uint4s	r-uint4z*Four-byte unsigned integer, little-endian.cCsB|jd}t|dkr2td|dStddS)z
    >>> import io
    >>> read_uint8(io.BytesIO(b'\xff\x00\x00\x00\x00\x00\x00\x00'))
    255
    >>> read_uint8(io.BytesIO(b'\xff' * 8)) == 2**64-1
    True
    z<Qrz'not enough data in stream to read uint8N)r!r'r(r")r#r$rrr
read_uint8&s	r0uint8r/z+Eight-byte unsigned integer, little-endian.TcCs|j}|jds'td|dd}|rxcdD]K}|j|rD|j|s~td||f|dd
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    >>> import io
    >>> read_stringnl(io.BytesIO(b"'abcd'\nefg\n"))
    'abcd'

    >>> read_stringnl(io.BytesIO(b"\n"))
    Traceback (most recent call last):
    ...
    ValueError: no string quotes around b''

    >>> read_stringnl(io.BytesIO(b"\n"), stripquotes=False)
    ''

    >>> read_stringnl(io.BytesIO(b"''\n"))
    ''

    >>> read_stringnl(io.BytesIO(b'"abcd"'))
    Traceback (most recent call last):
    ...
    ValueError: no newline found when trying to read stringnl

    Embedded escapes are undone in the result.
    >>> read_stringnl(io.BytesIO(br"'a\n\\b\x00c\td'" + b"\n'e'"))
    'a\n\\b\x00c\td'
    s
z-no newline found when trying to read stringnlNr"'z,strinq quote %r not found at both ends of %rzno string quotes around %rrascii)r2r3r5)readlineendswithr"
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r>stringnlzA newline-terminated string.

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                   cCst|ddS)Nr<F)r>)r#rrrread_stringnl_noescapetsr@stringnl_noescapeaA newline-terminated string.

                        This is a str-style string, without embedded escapes,
                        or bracketing quotes.  It should consist solely of
                        printable ASCII characters.
                        cCsdt|t|fS)zp
    >>> import io
    >>> read_stringnl_noescape_pair(io.BytesIO(b"Queue\nEmpty\njunk"))
    'Queue Empty'
    z%s %s)r@)r#rrrread_stringnl_noescape_pairsrBstringnl_noescape_pairaA pair of newline-terminated strings.

                             These are str-style strings, without embedded
                             escapes, or bracketing quotes.  They should
                             consist solely of printable ASCII characters.
                             The pair is returned as a single string, with
                             a single blank separating the two strings.
                             cCslt|}|dkst|j|}t||krL|jdStd|t|fdS)z
    >>> import io
    >>> read_string1(io.BytesIO(b"\x00"))
    ''
    >>> read_string1(io.BytesIO(b"\x03abcdef"))
    'abc'
    rzlatin-1z2expected %d bytes in a string1, but only %d remainN)r%rr!r'r;r")r#rr$rrrread_string1s	
rDstring1zA counted string.

              The first argument is a 1-byte unsigned int giving the number
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              cCsvt|}|dkr(td||j|}t||krV|jdStd|t|fdS)aP
    >>> import io
    >>> read_string4(io.BytesIO(b"\x00\x00\x00\x00abc"))
    ''
    >>> read_string4(io.BytesIO(b"\x03\x00\x00\x00abcdef"))
    'abc'
    >>> read_string4(io.BytesIO(b"\x00\x00\x00\x03abcdef"))
    Traceback (most recent call last):
    ...
    ValueError: expected 50331648 bytes in a string4, but only 6 remain
    rzstring4 byte count < 0: %dzlatin-1z2expected %d bytes in a string4, but only %d remainN)r+r"r!r'r;)r#rr$rrrread_string4s

rFstring4zA counted string.

              The first argument is a 4-byte little-endian signed int giving
              the number of bytes in the string, and the second argument is
              that many bytes.
              cCsct|}|dkst|j|}t||krC|Std|t|fdS)z
    >>> import io
    >>> read_bytes1(io.BytesIO(b"\x00"))
    b''
    >>> read_bytes1(io.BytesIO(b"\x03abcdef"))
    b'abc'
    rz1expected %d bytes in a bytes1, but only %d remainN)r%rr!r'r")r#rr$rrrread_bytes1s	rHbytes1zA counted bytes string.

              The first argument is a 1-byte unsigned int giving the number
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              bytes.
              cCsct|}|dkst|j|}t||krC|Std|t|fdS)z
    >>> import io
    >>> read_bytes1(io.BytesIO(b"\x00"))
    b''
    >>> read_bytes1(io.BytesIO(b"\x03abcdef"))
    b'abc'
    rz1expected %d bytes in a bytes1, but only %d remainN)r%rr!r'r")r#rr$rrrrHs	zA counted bytes string.

              The first argument is a 1-byte unsigned int giving the number
              of bytes, and the second argument is that many bytes.
              cCst|}|dkst|tjkr=td||j|}t||krb|Std|t|fdS)aN
    >>> import io
    >>> read_bytes4(io.BytesIO(b"\x00\x00\x00\x00abc"))
    b''
    >>> read_bytes4(io.BytesIO(b"\x03\x00\x00\x00abcdef"))
    b'abc'
    >>> read_bytes4(io.BytesIO(b"\x00\x00\x00\x03abcdef"))
    Traceback (most recent call last):
    ...
    ValueError: expected 50331648 bytes in a bytes4, but only 6 remain
    rz#bytes4 byte count > sys.maxsize: %dz1expected %d bytes in a bytes4, but only %d remainN)r-rsysmaxsizer"r!r')r#rr$rrrread_bytes4s
rLbytes4zA counted bytes string.

              The first argument is a 4-byte little-endian unsigned int giving
              the number of bytes, and the second argument is that many bytes.
              cCst|}|dkst|tjkr=td||j|}t||krb|Std|t|fdS)a
    >>> import io, struct, sys
    >>> read_bytes8(io.BytesIO(b"\x00\x00\x00\x00\x00\x00\x00\x00abc"))
    b''
    >>> read_bytes8(io.BytesIO(b"\x03\x00\x00\x00\x00\x00\x00\x00abcdef"))
    b'abc'
    >>> bigsize8 = struct.pack("<Q", sys.maxsize//3)
    >>> read_bytes8(io.BytesIO(bigsize8 + b"abcdef"))  #doctest: +ELLIPSIS
    Traceback (most recent call last):
    ...
    ValueError: expected ... bytes in a bytes8, but only 6 remain
    rz#bytes8 byte count > sys.maxsize: %dz1expected %d bytes in a bytes8, but only %d remainN)r0rrJrKr"r!r')r#rr$rrrread_bytes83srNbytes8zA counted bytes string.

              The first argument is an 8-byte little-endian unsigned int giving
              the number of bytes, and the second argument is that many bytes.
              cCsD|j}|jds'td|dd}t|dS)zm
    >>> import io
    >>> read_unicodestringnl(io.BytesIO(b"abc\\uabcd\njunk")) == 'abc\uabcd'
    True
    s
z4no newline found when trying to read unicodestringnlNrzraw-unicode-escaper5)r6r7r"r)r#r$rrrread_unicodestringnlUs
rPunicodestringnlzA newline-terminated Unicode string.

                      This is raw-unicode-escape encoded, so consists of
                      printable ASCII characters, and may contain embedded
                      escape sequences.
                      cCsot|}|dkst|j|}t||krOt|ddStd|t|fdS)a
    >>> import io
    >>> s = 'abcd\uabcd'
    >>> enc = s.encode('utf-8')
    >>> enc
    b'abcd\xea\xaf\x8d'
    >>> n = bytes([len(enc)])  # little-endian 1-byte length
    >>> t = read_unicodestring1(io.BytesIO(n + enc + b'junk'))
    >>> s == t
    True

    >>> read_unicodestring1(io.BytesIO(n + enc[:-1]))
    Traceback (most recent call last):
    ...
    ValueError: expected 7 bytes in a unicodestring1, but only 6 remain
    rzutf-8
surrogatepassz9expected %d bytes in a unicodestring1, but only %d remainN)r%rr!r'rr")r#rr$rrrread_unicodestring1osrSunicodestring1aAA counted Unicode string.

                    The first argument is a 1-byte little-endian signed int
                    giving the number of bytes in the string, and the second
                    argument-- the UTF-8 encoding of the Unicode string --
                    contains that many bytes.
                    cCst|}|dkst|tjkr=td||j|}t||krnt|ddStd|t|fdS)a
    >>> import io
    >>> s = 'abcd\uabcd'
    >>> enc = s.encode('utf-8')
    >>> enc
    b'abcd\xea\xaf\x8d'
    >>> n = bytes([len(enc), 0, 0, 0])  # little-endian 4-byte length
    >>> t = read_unicodestring4(io.BytesIO(n + enc + b'junk'))
    >>> s == t
    True

    >>> read_unicodestring4(io.BytesIO(n + enc[:-1]))
    Traceback (most recent call last):
    ...
    ValueError: expected 7 bytes in a unicodestring4, but only 6 remain
    rz+unicodestring4 byte count > sys.maxsize: %dzutf-8rRz9expected %d bytes in a unicodestring4, but only %d remainN)r-rrJrKr"r!r'r)r#rr$rrrread_unicodestring4srUunicodestring4aAA counted Unicode string.

                    The first argument is a 4-byte little-endian signed int
                    giving the number of bytes in the string, and the second
                    argument-- the UTF-8 encoding of the Unicode string --
                    contains that many bytes.
                    cCst|}|dkst|tjkr=td||j|}t||krnt|ddStd|t|fdS)a
    >>> import io
    >>> s = 'abcd\uabcd'
    >>> enc = s.encode('utf-8')
    >>> enc
    b'abcd\xea\xaf\x8d'
    >>> n = bytes([len(enc)]) + bytes(7)  # little-endian 8-byte length
    >>> t = read_unicodestring8(io.BytesIO(n + enc + b'junk'))
    >>> s == t
    True

    >>> read_unicodestring8(io.BytesIO(n + enc[:-1]))
    Traceback (most recent call last):
    ...
    ValueError: expected 7 bytes in a unicodestring8, but only 6 remain
    rz+unicodestring8 byte count > sys.maxsize: %dzutf-8rRz9expected %d bytes in a unicodestring8, but only %d remainN)r0rrJrKr"r!r'r)r#rr$rrrread_unicodestring8srWunicodestring8aBA counted Unicode string.

                    The first argument is an 8-byte little-endian signed int
                    giving the number of bytes in the string, and the second
                    argument-- the UTF-8 encoding of the Unicode string --
                    contains that many bytes.
                    cCsBt|dddd}|dkr(dS|dkr8dSt|S)z
    >>> import io
    >>> read_decimalnl_short(io.BytesIO(b"1234\n56"))
    1234

    >>> read_decimalnl_short(io.BytesIO(b"1234L\n56"))
    Traceback (most recent call last):
    ...
    ValueError: invalid literal for int() with base 10: b'1234L'
    r;Fr<s00s01T)r>r)r#srrrread_decimalnl_shortsrZcCsHt|dddd}|dddkr>|dd}t|S)	z
    >>> import io

    >>> read_decimalnl_long(io.BytesIO(b"1234L\n56"))
    1234

    >>> read_decimalnl_long(io.BytesIO(b"123456789012345678901234L\n6"))
    123456789012345678901234
    r;Fr<rNLr5r5)r>r)r#rYrrrread_decimalnl_longsr\decimalnl_shortaA newline-terminated decimal integer literal.

                          This never has a trailing 'L', and the integer fit
                          in a short Python int on the box where the pickle
                          was written -- but there's no guarantee it will fit
                          in a short Python int on the box where the pickle
                          is read.
                          decimalnl_longzA newline-terminated decimal integer literal.

                         This has a trailing 'L', and can represent integers
                         of any size.
                         cCs"t|dddd}t|S)zO
    >>> import io
    >>> read_floatnl(io.BytesIO(b"-1.25\n6"))
    -1.25
    r;Fr<)r>float)r#rYrrrread_floatnl'sr`floatnlaA newline-terminated decimal floating literal.

              In general this requires 17 significant digits for roundtrip
              identity, and pickling then unpickling infinities, NaNs, and
              minus zero doesn't work across boxes, or on some boxes even
              on itself (e.g., Windows can't read the strings it produces
              for infinities or NaNs).
              cCsB|jd}t|dkr2td|dStddS)z
    >>> import io, struct
    >>> raw = struct.pack(">d", -1.25)
    >>> raw
    b'\xbf\xf4\x00\x00\x00\x00\x00\x00'
    >>> read_float8(io.BytesIO(raw + b"\n"))
    -1.25
    r/z>drz(not enough data in stream to read float8N)r!r'r(r")r#r$rrrread_float8=s
rbfloat8aAn 8-byte binary representation of a float, big-endian.

             The format is unique to Python, and shared with the struct
             module (format string '>d') "in theory" (the struct and pickle
             implementations don't share the code -- they should).  It's
             strongly related to the IEEE-754 double format, and, in normal
             cases, is in fact identical to the big-endian 754 double format.
             On other boxes the dynamic range is limited to that of a 754
             double, and "add a half and chop" rounding is used to reduce
             the precision to 53 bits.  However, even on a 754 box,
             infinities, NaNs, and minus zero may not be handled correctly
             (may not survive roundtrip pickling intact).
             )decode_longcCsCt|}|j|}t||kr9tdt|S)a+
    >>> import io
    >>> read_long1(io.BytesIO(b"\x00"))
    0
    >>> read_long1(io.BytesIO(b"\x02\xff\x00"))
    255
    >>> read_long1(io.BytesIO(b"\x02\xff\x7f"))
    32767
    >>> read_long1(io.BytesIO(b"\x02\x00\xff"))
    -256
    >>> read_long1(io.BytesIO(b"\x02\x00\x80"))
    -32768
    z'not enough data in stream to read long1)r%r!r'r"rd)r#rr$rrr
read_long1cs
relong1aA binary long, little-endian, using 1-byte size.

    This first reads one byte as an unsigned size, then reads that
    many bytes and interprets them as a little-endian 2's-complement long.
    If the size is 0, that's taken as a shortcut for the long 0L.
    cCs_t|}|dkr(td||j|}t||krUtdt|S)ag
    >>> import io
    >>> read_long4(io.BytesIO(b"\x02\x00\x00\x00\xff\x00"))
    255
    >>> read_long4(io.BytesIO(b"\x02\x00\x00\x00\xff\x7f"))
    32767
    >>> read_long4(io.BytesIO(b"\x02\x00\x00\x00\x00\xff"))
    -256
    >>> read_long4(io.BytesIO(b"\x02\x00\x00\x00\x00\x80"))
    -32768
    >>> read_long1(io.BytesIO(b"\x00\x00\x00\x00"))
    0
    rzlong4 byte count < 0: %dz'not enough data in stream to read long4)r+r"r!r'rd)r#rr$rrr
read_long4srglong4aA binary representation of a long, little-endian.

    This first reads four bytes as a signed size (but requires the
    size to be >= 0), then reads that many bytes and interprets them
    as a little-endian 2's-complement long.  If the size is 0, that's taken
    as a shortcut for the int 0, although LONG1 should really be used
    then instead (and in any case where # of bytes < 256).
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      ZBININT1KzPush a one-byte unsigned integer.

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      ZBININT2MzPush a two-byte unsigned integer.

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      ZLONG1Šz|Long integer using one-byte length.

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      Z	BINSTRINGTaPush a Python string object.

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      'ASCII'.  If the encoding given was 'bytes' however, they will be
      decoded as bytes object instead.
      ZSHORT_BINSTRINGUaPush a Python string object.

      There are two arguments: the first is a 1-byte unsigned int giving
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      the Unpickler constructor. or the default, 'ASCII'.  If the
      encoding given was 'bytes' however, they will be decoded as bytes
      object instead.
      ZBINBYTESBzPush a Python bytes object.

      There are two arguments:  the first is a 4-byte little-endian unsigned int
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      ZSHORT_BINBYTESCzPush a Python bytes object.

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      Z	BINBYTES8ŽzPush a Python bytes object.

      There are two arguments:  the first is an 8-byte unsigned int giving
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      ZNONENzPush None on the stack.ZNEWTRUEˆz&True.

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      Push False onto the stack.UNICODEVzPush a Python Unicode string object.

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      until the next newline character.
      ZSHORT_BINUNICODEŒaPush a Python Unicode string object.

      There are two arguments:  the first is a 1-byte little-endian signed int
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      bytes, and is the UTF-8 encoding of the Unicode string.
      Z
BINUNICODEXaPush a Python Unicode string object.

      There are two arguments:  the first is a 4-byte little-endian unsigned int
      giving the number of bytes in the string.  The second is that many
      bytes, and is the UTF-8 encoding of the Unicode string.
      ZBINUNICODE8aPush a Python Unicode string object.

      There are two arguments:  the first is an 8-byte little-endian signed int
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      ZFLOATFaNewline-terminated decimal float literal.

      The argument is repr(a_float), and in general requires 17 significant
      digits for roundtrip conversion to be an identity (this is so for
      IEEE-754 double precision values, which is what Python float maps to
      on most boxes).

      In general, FLOAT cannot be used to transport infinities, NaNs, or
      minus zero across boxes (or even on a single box, if the platform C
      library can't read the strings it produces for such things -- Windows
      is like that), but may do less damage than BINFLOAT on boxes with
      greater precision or dynamic range than IEEE-754 double.
      ZBINFLOATGaFloat stored in binary form, with 8 bytes of data.

      This generally requires less than half the space of FLOAT encoding.
      In general, BINFLOAT cannot be used to transport infinities, NaNs, or
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      an IEEE-754 double, and retains no more than 53 bits of precision (if
      there are more than that, "add a half and chop" rounding is used to
      cut it back to 53 significant bits).
      Z
EMPTY_LIST]zPush an empty list.ZAPPENDazAppend an object to a list.

      Stack before:  ... pylist anyobject
      Stack after:   ... pylist+[anyobject]

      although pylist is really extended in-place.
      ZAPPENDSezExtend a list by a slice of stack objects.

      Stack before:  ... pylist markobject stackslice
      Stack after:   ... pylist+stackslice

      although pylist is really extended in-place.
      ZLISTlasBuild a list out of the topmost stack slice, after markobject.

      All the stack entries following the topmost markobject are placed into
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      Stack after:  ... [1, 2, 3, 'abc']
      ZEMPTY_TUPLE)zPush an empty tuple.ZTUPLEtavBuild a tuple out of the topmost stack slice, after markobject.

      All the stack entries following the topmost markobject are placed into
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      Stack before: ... markobject 1 2 3 'abc'
      Stack after:  ... (1, 2, 3, 'abc')
      ZTUPLE1…zBuild a one-tuple out of the topmost item on the stack.

      This code pops one value off the stack and pushes a tuple of
      length 1 whose one item is that value back onto it.  In other
      words:

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      ZTUPLE2†aBuild a two-tuple out of the top two items on the stack.

      This code pops two values off the stack and pushes a tuple of
      length 2 whose items are those values back onto it.  In other
      words:

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      ZTUPLE3‡aBuild a three-tuple out of the top three items on the stack.

      This code pops three values off the stack and pushes a tuple of
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      words:

          stack[-3:] = [tuple(stack[-3:])]
      Z
EMPTY_DICT}zPush an empty dict.ZDICTdaBuild a dict out of the topmost stack slice, after markobject.

      All the stack entries following the topmost markobject are placed into
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      stack from the topmost markobject onward.  The stack slice alternates
      key, value, key, value, ....  For example,

      Stack before: ... markobject 1 2 3 'abc'
      Stack after:  ... {1: 2, 3: 'abc'}
      ZSETITEMrYzAdd a key+value pair to an existing dict.

      Stack before:  ... pydict key value
      Stack after:   ... pydict

      where pydict has been modified via pydict[key] = value.
      ZSETITEMSua\Add an arbitrary number of key+value pairs to an existing dict.

      The slice of the stack following the topmost markobject is taken as
      an alternating sequence of keys and values, added to the dict
      immediately under the topmost markobject.  Everything at and after the
      topmost markobject is popped, leaving the mutated dict at the top
      of the stack.

      Stack before:  ... pydict markobject key_1 value_1 ... key_n value_n
      Stack after:   ... pydict

      where pydict has been modified via pydict[key_i] = value_i for i in
      1, 2, ..., n, and in that order.
      Z	EMPTY_SETzPush an empty set.ZADDITEMSa$Add an arbitrary number of items to an existing set.

      The slice of the stack following the topmost markobject is taken as
      a sequence of items, added to the set immediately under the topmost
      markobject.  Everything at and after the topmost markobject is popped,
      leaving the mutated set at the top of the stack.

      Stack before:  ... pyset markobject item_1 ... item_n
      Stack after:   ... pyset

      where pyset has been modified via pyset.add(item_i) = item_i for i in
      1, 2, ..., n, and in that order.
      Z	FROZENSET‘azBuild a frozenset out of the topmost slice, after markobject.

      All the stack entries following the topmost markobject are placed into
      a single Python frozenset, which single frozenset object replaces all
      of the stack from the topmost markobject onward.  For example,

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      Stack after:  ... frozenset({1, 2, 3})
      POP0z<Discard the top stack item, shrinking the stack by one item.ZDUP2z=Push the top stack item onto the stack again, duplicating it.MARK(zPush markobject onto the stack.

      markobject is a unique object, used by other opcodes to identify a
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      to work on.  See markobject.doc for more detail.
      ZPOP_MARK1aPop all the stack objects at and above the topmost markobject.

      When an opcode using a variable number of stack objects is done,
      POP_MARK is used to remove those objects, and to remove the markobject
      that delimited their starting position on the stack.
      GETgzRead an object from the memo and push it on the stack.

      The index of the memo object to push is given by the newline-terminated
      decimal string following.  BINGET and LONG_BINGET are space-optimized
      versions.
      BINGEThzRead an object from the memo and push it on the stack.

      The index of the memo object to push is given by the 1-byte unsigned
      integer following.
      LONG_BINGETjzRead an object from the memo and push it on the stack.

      The index of the memo object to push is given by the 4-byte unsigned
      little-endian integer following.
      PUTpzStore the stack top into the memo.  The stack is not popped.

      The index of the memo location to write into is given by the newline-
      terminated decimal string following.  BINPUT and LONG_BINPUT are
      space-optimized versions.
      BINPUTr=zStore the stack top into the memo.  The stack is not popped.

      The index of the memo location to write into is given by the 1-byte
      unsigned integer following.
      LONG_BINPUTrzStore the stack top into the memo.  The stack is not popped.

      The index of the memo location to write into is given by the 4-byte
      unsigned little-endian integer following.
      MEMOIZE”zStore the stack top into the memo.  The stack is not popped.

      The index of the memo location to write is the number of
      elements currently present in the memo.
      ZEXT1‚aExtension code.

      This code and the similar EXT2 and EXT4 allow using a registry
      of popular objects that are pickled by name, typically classes.
      It is envisioned that through a global negotiation and
      registration process, third parties can set up a mapping between
      ints and object names.

      In order to guarantee pickle interchangeability, the extension
      code registry ought to be global, although a range of codes may
      be reserved for private use.

      EXT1 has a 1-byte integer argument.  This is used to index into the
      extension registry, and the object at that index is pushed on the stack.
      ZEXT2ƒzNExtension code.

      See EXT1.  EXT2 has a two-byte integer argument.
      ZEXT4„zOExtension code.

      See EXT1.  EXT4 has a four-byte integer argument.
      ZGLOBALcaPush a global object (module.attr) on the stack.

      Two newline-terminated strings follow the GLOBAL opcode.  The first is
      taken as a module name, and the second as a class name.  The class
      object module.class is pushed on the stack.  More accurately, the
      object returned by self.find_class(module, class) is pushed on the
      stack, so unpickling subclasses can override this form of lookup.
      ZSTACK_GLOBAL“z7Push a global object (module.attr) on the stack.
      ZREDUCERaLPush an object built from a callable and an argument tuple.

      The opcode is named to remind of the __reduce__() method.

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      Stack after:  ... callable(*pytuple)

      The callable and the argument tuple are the first two items returned
      by a __reduce__ method.  Applying the callable to the argtuple is
      supposed to reproduce the original object, or at least get it started.
      If the __reduce__ method returns a 3-tuple, the last component is an
      argument to be passed to the object's __setstate__, and then the REDUCE
      opcode is followed by code to create setstate's argument, and then a
      BUILD opcode to apply  __setstate__ to that argument.

      If not isinstance(callable, type), REDUCE complains unless the
      callable has been registered with the copyreg module's
      safe_constructors dict, or the callable has a magic
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      ZBUILDbaFinish building an object, via __setstate__ or dict update.

      Stack before: ... anyobject argument
      Stack after:  ... anyobject

      where anyobject may have been mutated, as follows:

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          anyobject.__setstate__(argument)

      is called.

      Else the argument must be a dict, the object must have a __dict__, and
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      ZINSTiaqBuild a class instance.

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      INST is followed by two newline-terminated strings, giving a
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      In addition, all the objects on the stack following the topmost
      markobject are gathered into a tuple and popped (along with the
      topmost markobject), just as for the TUPLE opcode.

      Now it gets complicated.  If all of these are true:

        + The argtuple is empty (markobject was at the top of the stack
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        + The class object does not have a __getinitargs__ attribute.

      then we want to create an old-style class instance without invoking
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      the new instance object is pushed on the stack, and we're done.

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      NOTE:  checks for __safe_for_unpickling__ went away in Python 2.3.
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      ZOBJoaBuild a class instance.

      This is the protocol 1 version of protocol 0's INST opcode, and is
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      Unlike INST, OBJ takes no arguments from the opcode stream.  Instead
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      Stack after:  ... new_instance_object

      As for INST, the remainder of the stack above the markobject is
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      ZNEWOBJaLBuild an object instance.

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      Z	NEWOBJ_EX’auBuild an object instance.

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      STOP.zStop the unpickling machine.

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      FRAME•zIndicate the beginning of a new frame.

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|j|qGWtd|d||ratd|dS)'aKProduce a symbolic disassembly of a pickle.

    'pickle' is a file-like object, or string, containing a (at least one)
    pickle.  The pickle is disassembled from the current position, through
    the first STOP opcode encountered.

    Optional arg 'out' is a file-like object to which the disassembly is
    printed.  It defaults to sys.stdout.

    Optional arg 'memo' is a Python dict, used as the pickle's memo.  It
    may be mutated by dis(), if the pickle contains PUT or BINPUT opcodes.
    Passing the same memo object to another dis() call then allows disassembly
    to proceed across multiple pickles that were all created by the same
    pickler with the same memo.  Ordinarily you don't need to worry about this.

    Optional arg 'indentlevel' is the number of blanks by which to indent
    a new MARK level.  It defaults to 4.

    Optional arg 'annotate' if nonzero instructs dis() to add short
    description of the opcode on each line of disassembled output.
    The value given to 'annotate' must be an integer and is used as a
    hint for the column where annotation should start.  The default
    value is 0, meaning no annotations.

    In addition to printing the disassembly, some sanity checks are made:

    + All embedded opcode arguments "make sense".

    + Explicit and implicit pop operations have enough items on the stack.

    + When an opcode implicitly refers to a markobject, a markobject is
      actually on the stack.

    + A memo entry isn't referenced before it's defined.

    + The markobject isn't stored in the memo.

    + A memo entry isn't redefined.
    Nr z%5d:endfilez	%-4s %s%srz(MARK at unknown opcode offset)z(MARK at %d)rzno MARK exists on stackrrrrzmemo key %r already definedz'stack is empty -- can't store into memoz"can't store markobject in the memorrrz&memo key %r has never been stored into
2rz3tries to pop %d items from stack with only %d itemsz highest protocol among opcodes =zstack not empty after STOP: %rr5r5r5r5r5)rrrrr5r5)rrr)rrreprrxr'rmaxr|rzr{
markobjectrrvpopindexr"rsplitrextend)r}rmemoindentlevelannotatestackZmaxprotoZ	markstackZindentchunkZerrormsgZannocolrryrlineZbeforeZafterZnumtopopZmarkmsgZmarkposZmemo_idxrrrr)	s-


			




		
!
c@seZdZddZdS)_ExamplecCs
||_dS)N)value)rrrrrr	sz_Example.__init__N)rrrrrrrrr	sra
>>> import pickle
>>> x = [1, 2, (3, 4), {b'abc': "def"}]
>>> pkl0 = pickle.dumps(x, 0)
>>> dis(pkl0)
    0: (    MARK
    1: l        LIST       (MARK at 0)
    2: p    PUT        0
    5: L    LONG       1
    9: a    APPEND
   10: L    LONG       2
   14: a    APPEND
   15: (    MARK
   16: L        LONG       3
   20: L        LONG       4
   24: t        TUPLE      (MARK at 15)
   25: p    PUT        1
   28: a    APPEND
   29: (    MARK
   30: d        DICT       (MARK at 29)
   31: p    PUT        2
   34: c    GLOBAL     '_codecs encode'
   50: p    PUT        3
   53: (    MARK
   54: V        UNICODE    'abc'
   59: p        PUT        4
   62: V        UNICODE    'latin1'
   70: p        PUT        5
   73: t        TUPLE      (MARK at 53)
   74: p    PUT        6
   77: R    REDUCE
   78: p    PUT        7
   81: V    UNICODE    'def'
   86: p    PUT        8
   89: s    SETITEM
   90: a    APPEND
   91: .    STOP
highest protocol among opcodes = 0

Try again with a "binary" pickle.

>>> pkl1 = pickle.dumps(x, 1)
>>> dis(pkl1)
    0: ]    EMPTY_LIST
    1: q    BINPUT     0
    3: (    MARK
    4: K        BININT1    1
    6: K        BININT1    2
    8: (        MARK
    9: K            BININT1    3
   11: K            BININT1    4
   13: t            TUPLE      (MARK at 8)
   14: q        BINPUT     1
   16: }        EMPTY_DICT
   17: q        BINPUT     2
   19: c        GLOBAL     '_codecs encode'
   35: q        BINPUT     3
   37: (        MARK
   38: X            BINUNICODE 'abc'
   46: q            BINPUT     4
   48: X            BINUNICODE 'latin1'
   59: q            BINPUT     5
   61: t            TUPLE      (MARK at 37)
   62: q        BINPUT     6
   64: R        REDUCE
   65: q        BINPUT     7
   67: X        BINUNICODE 'def'
   75: q        BINPUT     8
   77: s        SETITEM
   78: e        APPENDS    (MARK at 3)
   79: .    STOP
highest protocol among opcodes = 1

Exercise the INST/OBJ/BUILD family.

>>> import pickletools
>>> dis(pickle.dumps(pickletools.dis, 0))
    0: c    GLOBAL     'pickletools dis'
   17: p    PUT        0
   20: .    STOP
highest protocol among opcodes = 0

>>> from pickletools import _Example
>>> x = [_Example(42)] * 2
>>> dis(pickle.dumps(x, 0))
    0: (    MARK
    1: l        LIST       (MARK at 0)
    2: p    PUT        0
    5: c    GLOBAL     'copy_reg _reconstructor'
   30: p    PUT        1
   33: (    MARK
   34: c        GLOBAL     'pickletools _Example'
   56: p        PUT        2
   59: c        GLOBAL     '__builtin__ object'
   79: p        PUT        3
   82: N        NONE
   83: t        TUPLE      (MARK at 33)
   84: p    PUT        4
   87: R    REDUCE
   88: p    PUT        5
   91: (    MARK
   92: d        DICT       (MARK at 91)
   93: p    PUT        6
   96: V    UNICODE    'value'
  103: p    PUT        7
  106: L    LONG       42
  111: s    SETITEM
  112: b    BUILD
  113: a    APPEND
  114: g    GET        5
  117: a    APPEND
  118: .    STOP
highest protocol among opcodes = 0

>>> dis(pickle.dumps(x, 1))
    0: ]    EMPTY_LIST
    1: q    BINPUT     0
    3: (    MARK
    4: c        GLOBAL     'copy_reg _reconstructor'
   29: q        BINPUT     1
   31: (        MARK
   32: c            GLOBAL     'pickletools _Example'
   54: q            BINPUT     2
   56: c            GLOBAL     '__builtin__ object'
   76: q            BINPUT     3
   78: N            NONE
   79: t            TUPLE      (MARK at 31)
   80: q        BINPUT     4
   82: R        REDUCE
   83: q        BINPUT     5
   85: }        EMPTY_DICT
   86: q        BINPUT     6
   88: X        BINUNICODE 'value'
   98: q        BINPUT     7
  100: K        BININT1    42
  102: s        SETITEM
  103: b        BUILD
  104: h        BINGET     5
  106: e        APPENDS    (MARK at 3)
  107: .    STOP
highest protocol among opcodes = 1

Try "the canonical" recursive-object test.

>>> L = []
>>> T = L,
>>> L.append(T)
>>> L[0] is T
True
>>> T[0] is L
True
>>> L[0][0] is L
True
>>> T[0][0] is T
True
>>> dis(pickle.dumps(L, 0))
    0: (    MARK
    1: l        LIST       (MARK at 0)
    2: p    PUT        0
    5: (    MARK
    6: g        GET        0
    9: t        TUPLE      (MARK at 5)
   10: p    PUT        1
   13: a    APPEND
   14: .    STOP
highest protocol among opcodes = 0

>>> dis(pickle.dumps(L, 1))
    0: ]    EMPTY_LIST
    1: q    BINPUT     0
    3: (    MARK
    4: h        BINGET     0
    6: t        TUPLE      (MARK at 3)
    7: q    BINPUT     1
    9: a    APPEND
   10: .    STOP
highest protocol among opcodes = 1

Note that, in the protocol 0 pickle of the recursive tuple, the disassembler
has to emulate the stack in order to realize that the POP opcode at 16 gets
rid of the MARK at 0.

>>> dis(pickle.dumps(T, 0))
    0: (    MARK
    1: (        MARK
    2: l            LIST       (MARK at 1)
    3: p        PUT        0
    6: (        MARK
    7: g            GET        0
   10: t            TUPLE      (MARK at 6)
   11: p        PUT        1
   14: a        APPEND
   15: 0        POP
   16: 0        POP        (MARK at 0)
   17: g    GET        1
   20: .    STOP
highest protocol among opcodes = 0

>>> dis(pickle.dumps(T, 1))
    0: (    MARK
    1: ]        EMPTY_LIST
    2: q        BINPUT     0
    4: (        MARK
    5: h            BINGET     0
    7: t            TUPLE      (MARK at 4)
    8: q        BINPUT     1
   10: a        APPEND
   11: 1        POP_MARK   (MARK at 0)
   12: h    BINGET     1
   14: .    STOP
highest protocol among opcodes = 1

Try protocol 2.

>>> dis(pickle.dumps(L, 2))
    0: \x80 PROTO      2
    2: ]    EMPTY_LIST
    3: q    BINPUT     0
    5: h    BINGET     0
    7: \x85 TUPLE1
    8: q    BINPUT     1
   10: a    APPEND
   11: .    STOP
highest protocol among opcodes = 2

>>> dis(pickle.dumps(T, 2))
    0: \x80 PROTO      2
    2: ]    EMPTY_LIST
    3: q    BINPUT     0
    5: h    BINGET     0
    7: \x85 TUPLE1
    8: q    BINPUT     1
   10: a    APPEND
   11: 0    POP
   12: h    BINGET     1
   14: .    STOP
highest protocol among opcodes = 2

Try protocol 3 with annotations:

>>> dis(pickle.dumps(T, 3), annotate=1)
    0: \x80 PROTO      3 Protocol version indicator.
    2: ]    EMPTY_LIST   Push an empty list.
    3: q    BINPUT     0 Store the stack top into the memo.  The stack is not popped.
    5: h    BINGET     0 Read an object from the memo and push it on the stack.
    7: \x85 TUPLE1       Build a one-tuple out of the topmost item on the stack.
    8: q    BINPUT     1 Store the stack top into the memo.  The stack is not popped.
   10: a    APPEND       Append an object to a list.
   11: 0    POP          Discard the top stack item, shrinking the stack by one item.
   12: h    BINGET     1 Read an object from the memo and push it on the stack.
   14: .    STOP         Stop the unpickling machine.
highest protocol among opcodes = 2

a=
>>> import pickle
>>> import io
>>> f = io.BytesIO()
>>> p = pickle.Pickler(f, 2)
>>> x = [1, 2, 3]
>>> p.dump(x)
>>> p.dump(x)
>>> f.seek(0)
0
>>> memo = {}
>>> dis(f, memo=memo)
    0: \x80 PROTO      2
    2: ]    EMPTY_LIST
    3: q    BINPUT     0
    5: (    MARK
    6: K        BININT1    1
    8: K        BININT1    2
   10: K        BININT1    3
   12: e        APPENDS    (MARK at 5)
   13: .    STOP
highest protocol among opcodes = 2
>>> dis(f, memo=memo)
   14: \x80 PROTO      2
   16: h    BINGET     0
   18: .    STOP
highest protocol among opcodes = 2
Zdisassembler_testZdisassembler_memo_testcCsddl}|jS)Nr)doctestZtestmod)rrrr_test
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